TSTP Solution File: SEV240^5 by Duper---1.0
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% File : Duper---1.0
% Problem : SEV240^5 : TPTP v8.1.2. Released v4.0.0.
% Transfm : none
% Format : tptp:raw
% Command : duper %s
% Computer : n018.cluster.edu
% Model : x86_64 x86_64
% CPU : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory : 8042.1875MB
% OS : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit : 300s
% DateTime : Thu Aug 31 19:24:34 EDT 2023
% Result : Theorem 3.51s 3.77s
% Output : Proof 3.51s
% Verified :
% SZS Type : -
% Comments :
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12 % Problem : SEV240^5 : TPTP v8.1.2. Released v4.0.0.
% 0.00/0.13 % Command : duper %s
% 0.14/0.34 % Computer : n018.cluster.edu
% 0.14/0.34 % Model : x86_64 x86_64
% 0.14/0.34 % CPU : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.14/0.34 % Memory : 8042.1875MB
% 0.14/0.34 % OS : Linux 3.10.0-693.el7.x86_64
% 0.14/0.34 % CPULimit : 300
% 0.14/0.34 % WCLimit : 300
% 0.14/0.34 % DateTime : Thu Aug 24 02:58:12 EDT 2023
% 0.14/0.35 % CPUTime :
% 3.51/3.77 SZS status Theorem for theBenchmark.p
% 3.51/3.77 SZS output start Proof for theBenchmark.p
% 3.51/3.77 Clause #0 (by assumption #[]): Eq (Not (∀ (Xx : a → Prop), cA Xx → ∀ (Xx0 : a), Xx Xx0 → Exists fun S => And (cA S) (S Xx0))) True
% 3.51/3.77 Clause #1 (by clausification #[0]): Eq (∀ (Xx : a → Prop), cA Xx → ∀ (Xx0 : a), Xx Xx0 → Exists fun S => And (cA S) (S Xx0)) False
% 3.51/3.77 Clause #2 (by clausification #[1]): ∀ (a_1 : a → Prop), Eq (Not (cA (skS.0 0 a_1) → ∀ (Xx0 : a), skS.0 0 a_1 Xx0 → Exists fun S => And (cA S) (S Xx0))) True
% 3.51/3.77 Clause #3 (by clausification #[2]): ∀ (a_1 : a → Prop), Eq (cA (skS.0 0 a_1) → ∀ (Xx0 : a), skS.0 0 a_1 Xx0 → Exists fun S => And (cA S) (S Xx0)) False
% 3.51/3.77 Clause #4 (by clausification #[3]): ∀ (a_1 : a → Prop), Eq (cA (skS.0 0 a_1)) True
% 3.51/3.77 Clause #5 (by clausification #[3]): ∀ (a_1 : a → Prop), Eq (∀ (Xx0 : a), skS.0 0 a_1 Xx0 → Exists fun S => And (cA S) (S Xx0)) False
% 3.51/3.77 Clause #6 (by clausification #[5]): ∀ (a_1 : a → Prop) (a_2 : a),
% 3.51/3.77 Eq (Not (skS.0 0 a_1 (skS.0 1 a_1 a_2) → Exists fun S => And (cA S) (S (skS.0 1 a_1 a_2)))) True
% 3.51/3.77 Clause #7 (by clausification #[6]): ∀ (a_1 : a → Prop) (a_2 : a),
% 3.51/3.77 Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2) → Exists fun S => And (cA S) (S (skS.0 1 a_1 a_2))) False
% 3.51/3.77 Clause #8 (by clausification #[7]): ∀ (a_1 : a → Prop) (a_2 : a), Eq (skS.0 0 a_1 (skS.0 1 a_1 a_2)) True
% 3.51/3.77 Clause #9 (by clausification #[7]): ∀ (a_1 : a → Prop) (a_2 : a), Eq (Exists fun S => And (cA S) (S (skS.0 1 a_1 a_2))) False
% 3.51/3.77 Clause #10 (by clausification #[9]): ∀ (a_1 a_2 : a → Prop) (a_3 : a), Eq (And (cA a_1) (a_1 (skS.0 1 a_2 a_3))) False
% 3.51/3.77 Clause #11 (by clausification #[10]): ∀ (a_1 a_2 : a → Prop) (a_3 : a), Or (Eq (cA a_1) False) (Eq (a_1 (skS.0 1 a_2 a_3)) False)
% 3.51/3.77 Clause #12 (by superposition #[11, 4]): ∀ (a_1 a_2 : a → Prop) (a_3 : a), Or (Eq ((fun x => skS.0 0 a_1 x) (skS.0 1 a_2 a_3)) False) (Eq False True)
% 3.51/3.77 Clause #13 (by betaEtaReduce #[12]): ∀ (a_1 a_2 : a → Prop) (a_3 : a), Or (Eq (skS.0 0 a_1 (skS.0 1 a_2 a_3)) False) (Eq False True)
% 3.51/3.77 Clause #14 (by clausification #[13]): ∀ (a_1 a_2 : a → Prop) (a_3 : a), Eq (skS.0 0 a_1 (skS.0 1 a_2 a_3)) False
% 3.51/3.77 Clause #15 (by superposition #[14, 8]): Eq False True
% 3.51/3.77 Clause #16 (by clausification #[15]): False
% 3.51/3.77 SZS output end Proof for theBenchmark.p
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